CaO + H2O = Ca(OH)2
n(CaO) = m/M = 5.5g/56g/mol = 0.098 mol
n(H2O) = 5.31g/18g/mol = 0.295 mol
According to the equation
n(CaO) : n(H2O) = 1:1
CaO reacts completely, H2O is in the excess.
0.098 mol H2O reacts with CaO.
n(H2O) = 0.295 - 0.098 = 0.197 mol of water will remain after the reaction is complete.
m(H2O) = 0.197mol*18g/mol = 3.546 g
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