1. Determine the amount of neat absorbed by the ice during melting:
"Q_f = 200 \\times 333 = 66600 \\;J"
2. Use the specific heat equation to determine the amount of heat absorbed by the water until its reaches the boiling point.
Q_w = mCΔT
"= 200 \\times 4.184 \\times 100 = 83680 \\;J"
3. Determine the amount of heat absorbed by the water during vaporization.
"Q_v = 200 \\times 2260 = 452000 \\:J"
4. Calculate the total energy absorbed during the entire process.
"Q_T = Q_f+Q_w+Q_v \\\\\n\nQ_T = 66600+83680+452000=602280 \\;J = 602.28 \\;kJ"
Answer: 602.28 kJ
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