1. Determine the amount of neat absorbed by the ice during melting:
Qf=200×333=66600J
2. Use the specific heat equation to determine the amount of heat absorbed by the water until its reaches the boiling point.
Q_w = mCΔT
=200×4.184×100=83680J
3. Determine the amount of heat absorbed by the water during vaporization.
Qv=200×2260=452000J
4. Calculate the total energy absorbed during the entire process.
QT=Qf+Qw+QvQT=66600+83680+452000=602280J=602.28kJ
Answer: 602.28 kJ
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