Answer to Question #151695 in General Chemistry for Mallory Chapman

Question

A system receives 425 J of heat and delivers 425 J of work to the surroundings. what is the change in internal energy of the system?

Answer 1

quantity of heat received,q = +425J

work done on the surrounding,w= -425J

Change in internal energy,∆E=?

∆E= q+w

∆E= +425 + (-425)

∆E= +425 - 425

∆E= 0