Empirical formula is "C_2OH_2"
The total molecular mass is
"(12.01*2)+(1*16.00)+(2*1.00)=42.02g\/mol"
The percentage hyroxide portion is
"12+2=14g\/mol"
"\\dfrac{14g\/mol}{42.02g\/mol}\u00d7100=33\\%"
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