Answer to Question #151644 in General Chemistry for Annika

Question #151644

What volume of 15.9 M Nitric acid would be required to make 3.2 L of 2.00 M nitric acid?

Expert's answer

using M₁V₁ = M₂V₂

15.9 × V₁ = 3.2×2

V₁ = 6.4/15.9 = 0.402 L

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