Question

To go forth with a reaction in a laboratory 250.0 ml of a solution is needed from an 0.03690 M in AgNo3 acqueose solution. How many grams of AgNo3 with a 87.90 pureness are needed to prepare the solution. Molar mass of AgNo3= 169.87g
Options:
A. 1.567 g
B. 6.268 g
C. 1.783 g
D. 7.132 g
E. 1.377 g

Answer 1

To find the mass we need to find the mole at first

Therefore using n=CV, we have;

n=0.25×0.03690

n=0.00923moles

From the formula; mole=mass/molar mass

We have mass=mole×molar mass

Mass=0.00923×169.87

Mass=1.567g

Therefore the answer is option (B)