Question

Calculate the hydrolysis constant of a sodium acetate solution, knowing that the acetic acid ionization constant at 25 oC is 1.8 x 10-5 and that the ionic product of water is 1.0 x 10-14 .

Answer 1

K _h=K_w/K_a

(1.0 x 10^-14 )/1.8 x 10^-5

=5.56x10^-10