Question #151355

Titanium (IV) oxide is the main pigment in white and other light – colored paints. How many grams of titanium(IV) oxide (80) will produce from 18.0 g of oxygen (16) react with Ti to form titanium(IV) oxide?


Expert's answer

Since the molecular mass of oxygen is given as 16, It is assumed that oxygen is atomic. If the assumption is wrong, divide the final answer by 2. Ti+2O→TiO2Ti + 2O \rightarrow TiO_2

n=m/Mn= m/M

M(O)=16gmolM(O) = 16\frac{g}{mol}

M(TiO2)=80gmolM(TiO_2) = 80\frac{g}{mol}

n(O)=n(TiO2)=18 g16gmol=1.125 moln(O) = n(TiO_2) =\frac {18\ g }{16\frac{g}{mol}} = 1. 125 \ mol

m=n∗Mm = n*M

m(TiO2)=1.125 mol∗80gmol=90 gm(TiO_2) = 1.125\ mol * 80\frac{g}{mol} =90\ g

Answer: m(TiO2)=90 gm(TiO_2) = 90\ g


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