Question #151355

Titanium (IV) oxide is the main pigment in white and other light – colored paints. How many grams of titanium(IV) oxide (80) will produce from 18.0 g of oxygen (16) react with Ti to form titanium(IV) oxide?


1
Expert's answer
2020-12-17T07:34:32-0500

Since the molecular mass of oxygen is given as 16, It is assumed that oxygen is atomic. If the assumption is wrong, divide the final answer by 2. Ti+2OTiO2Ti + 2O \rightarrow TiO_2

n=m/Mn= m/M

M(O)=16gmolM(O) = 16\frac{g}{mol}

M(TiO2)=80gmolM(TiO_2) = 80\frac{g}{mol}

n(O)=n(TiO2)=18 g16gmol=1.125 moln(O) = n(TiO_2) =\frac {18\ g }{16\frac{g}{mol}} = 1. 125 \ mol

m=nMm = n*M

m(TiO2)=1.125 mol80gmol=90 gm(TiO_2) = 1.125\ mol * 80\frac{g}{mol} =90\ g

Answer: m(TiO2)=90 gm(TiO_2) = 90\ g


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