T1=10°C=273K+10=283KP1=2.5atmT_1 = 10°C = 273K + 10 = 283K\\ P_1 = 2.5atmT1=10°C=273K+10=283KP1=2.5atm
T2=50°C=273K+50=323KP2=?T_2 = 50°C = 273K + 50 = 323K\\ P_2 = ?T2=50°C=273K+50=323KP2=?
Using Gay-Lussac's law,
P1/T1 = P2/T2
2.5/283 = P2/323
P2 = 2.5×323/283 = 2.853 atm
Therefore, the new pressure is 2.853 atm.
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments