Question

Calculate the heat change in kilojoules for vaporization of 4.00 kg of water at 100∘C.

Answer 1

100 ⁰C ------------------> 100 ⁰C

H₂O_(l) H₂O_(g)

Assume the heat change is Q,

$\begin {aligned} Q &= ML\\ &=4kg \times 2264.7 kJkg^{-1}\\ &=\bold{ 9058.8 kJ} \end {aligned}$