CoCl2=129.8392(gmole)CoCl_2=129.8392( \tfrac{g}{mole} )CoCl2=129.8392(moleg)
Cl2=70.9060(gmole)Cl_2=70.9060( \tfrac{g}{mole} )Cl2=70.9060(moleg)
70.9060(gmole)129.8392(gmole)=0.5461∗100%=54.6%\dfrac{70.9060( \tfrac{g}{mole} )}{129.8392( \tfrac{g}{mole} )} =0.5461*100\%=54.6\%129.8392(moleg)70.9060(moleg)=0.5461∗100%=54.6%
54.6% of chlorine in the chemical compound [cobalt (II) chloride].
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