Solutions:
mass of chlorine = 40g
mass of sodium = X ?
molar mass of sodium = 23 g/mol
molar mass of chlorine = 35.5 g/mol
Equation of the reaction:
2Na + Cl2 ----> 2NaCl
(2 × molar mass of Na) ====== (molar mass of chlorine × 2)
(2 × 23) ====== (35.5 × 2).
So, we have:
(46 g of sodium ) ===== (71 g of chlorine)
(X g of sodium) ====== ( 40g of chlorine)
cross multiply,
we have X = (46 × 40) / (71)
X = 25.91g of sodium.
25.91g of sodium are present.
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