Question

initially at human body temperature and 725mmHg, a 456mL sample of gas is cooled to -25.0 celsius while having pressure changed what is the volume of the sample

Answer 1

Gas Equation, $PV = n R T$ holds good in all situations.

Given, Pressure unchanged and no. of particles fixed,

P₁V₁= n R T₁ and P₂V2= n R T2

Dividing them, we get $\frac{V1}{V2} = \frac{T1}{T2}$

we need to find V2,

Therefore V2 = $\frac{V1T2}{T1}$

= 456 * 248/310

= 364.8 mL