Answer to Question #150781 in General Chemistry for Cj Tumambing

Question #150781
Calculate the pH of 0.17 propanoic acid, found in the sample analysis of sewage water.
1
Expert's answer
2020-12-14T14:43:11-0500

C2H5COOH --> C2H5COO- + H+

[H+] = 0.17 mole/L;

pH= -lg[H+]=-lg(0.17)=0.77

Answer: pH=0.77




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