Answer to Question #150781 in General Chemistry for Cj Tumambing

Question #150781

Calculate the pH of 0.17 propanoic acid, found in the sample analysis of sewage water.

Expert's answer

C₂H₅COOH --> C₂H₅COO^- + H⁺

[H⁺] = 0.17 mole/L;

pH= -lg[H⁺]=-lg(0.17)=0.77

Answer: pH=0.77

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