Answer to Question #150571 in General Chemistry for Reagan Hebert

Question

Given 812.5g of Sr2P3, how many atoms of strontium oxide can you produce?

Answer 1

Sr₃P₂+2H₂O=2Sr(OH)₂+2PH₃

find n Sr₃P₂

$n=\frac{m}{M}=\frac{812.5}{268.1620}=3.03$

find n Sr(OH)₂

$\frac{3.03}{1}=\frac{x}{2}$

x=6.06

Sr(OH)₂=SrO+H₂O

find n SrOH

$\frac{6.06}{1}=\frac{x}{1}$

x=6.06

find atoms SrO :

$N=Na\times n=6.022\times10^{23}\times6.06=36.49\times10^{23}$