Answer to Question #150489 in General Chemistry for Sophia

Question

How many moles of Cu(CH₃CO₂)₂ (MM: 149.65 g/mol) are present if you have 3.857 E+21 particles of it?

Answer 1

Solution:

One mole of any substance contains 6.022×10²³ particles.

Hence,

Moles of Cu(CH₃CO₂)₂ = (3.857×10²¹ particles / 6.022×10²³ particles) × 1 mol = 0.0064 moles

Moles of Cu(CH₃CO₂)₂ = 0.0064 moles

Answer: 0.0064 moles of Cu(CH₃CO₂)₂.