Answer to Question #150162 in General Chemistry for Jonalyn Fabito

General Chemistry

Question #150162

Calculate the molality of 10.94g C6H5OH in 220g of H20

Expert's answer

M = n (C6H5OH) / V раствор

М (C6H5OH) = 94

n (C6H5OH) = m / M = 10,94 / 94 = 0,116 моль

V (C6H5OH) = 0,116 * 22,4 = 2,6л

V (H2O) = 0,220 * 1 = 0,220л

М = 0,116 / 2,82 = 0,04

Learn more about our help with Assignments: Chemistry

Comments

No comments. Be the first!

Leave a comment

Related Questions

1. 2Fe + 3Cl2 → 2FeCl3 how much iron (Fe) is needed to produce 4 moles of FeCl3? how much FeCl3 is p
2. what is the name of a zinc atom when it loses two electrons
3. A solution contains 1.5 g sodium chloride in 100.0 g water. What is the percentage by mass of NaCl i
4. write the chemical equation how many grams of water are produced when 2.50 mol oxygen gas reacts wit
5. A solution contains 10.0 g of carbon tetrachloride, CCl4, and 20.0 g of benzene, C6H6. Calculate the
6. A solution of magnesium sulfate is 0.0500 molal. Calculate the mass percentage of MgSO4 in this solu
7. Calculate the mass of potassium permanganate present in 500.0 mL of a 0.100 N solution.