Question

2Fe + 3Cl2 → 2FeCl3

how much iron (Fe) is needed to produce 4 moles of FeCl3?
how much FeCl3 is produced when 5 moles of Fe react in excess chlorine?

Answer 1

$2Fe + 3Cl2 → 2FeCl3$

$2×4moles of FeCl3=8mol$

$Molar Mass of FeCl3=162.2g/mol$

$1 mol of FeCl3=162.2g$

$8mol=?$

$=8×162.2$

$Answer=1297.6g$

$Question2$

$2×5mol of Fe =10mol$

$Molar Mass of Fe =55.84g/mol$

$1 Mol of Fe =55.84g$

$10 mol of Fe =?$

$=55.84×10$

$Answer = 558.4g$