"pH = -log[H^+] \\\\\n\n[H^+] = 10^{-pH} \\\\\n\nSaliva \\; [H^+] = 10^{-6.38} = 4.1 \\times 10^{-7} \\;M \\\\\n\nBlood \\; [H^+] = 10^{-7.41} = 3.8 \\times 10^{-8} \\;M"
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