Question #149774
How many moles are contained in a 100.0 grams sample of iron
1
Expert's answer
2020-12-09T06:34:25-0500

M(Fe)=55.84  g/moln=mMn(Fe)=100.055.84=1.79  molM(Fe) = 55.84 \; g/mol \\ n = \frac{m}{M} \\ n(Fe) = \frac{100.0}{55.84} = 1.79 \;mol

Answer: 1.78 mol


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