Average speed
v=8RTπMv = \sqrt{\frac{8RT}{πM}}v=πM8RT
R = gas constant
T = temperature
M = molar mass
Since R and T are constants:
vv’=M’M\frac{v}{v’} = \sqrt{\frac{M’}{M}}v’v=MM’
v = velocity of H2 = 1700 m/s
v’ = velocity of O2
M(H2) = 2 g/mol
M(O2) = 32 g/mol
v’=vM(H2)M(O2)=1700232=1700×0.25=425 m/sv’ = v \sqrt{\frac{M(H_2)}{M(O_2)}} \\ = 1700 \sqrt{\frac{2}{32}} \\ = 1700 \times 0.25 \\ = 425 \; m/sv’=vM(O2)M(H2)=1700322=1700×0.25=425m/s
Answer: 425 m/s
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