Average speed
"v = \\sqrt{\\frac{8RT}{\u03c0M}}"
R = gas constant
T = temperature
M = molar mass
Since R and T are constants:
"\\frac{v}{v\u2019} = \\sqrt{\\frac{M\u2019}{M}}"
v = velocity of H2 = 1700 m/s
v’ = velocity of O2
M(H2) = 2 g/mol
M(O2) = 32 g/mol
"v\u2019 = v \\sqrt{\\frac{M(H_2)}{M(O_2)}} \\\\\n\n= 1700 \\sqrt{\\frac{2}{32}} \\\\\n\n= 1700 \\times 0.25 \\\\\n\n= 425 \\; m\/s"
Answer: 425 m/s
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