Answer to Question #149425 in General Chemistry for Vasava Siddharth

Question

Find the uncertainty in position of electron when the uncertainty in its velocity is 0.0005 % of velocity of light.

Answer 1

∆x∆p = h/4π

∆x (m∆v) = h/4π

∆x = h/(4πm∆v)

mass of electron is 9.1×10^-31 kg

∆v is given = 0.0005% × 3× 10⁸ m/s= 0.000005 × 3× 10⁸ m/s = 15 × 10³m/s

h = 6.626× 10^-34

on substituting these values we get

∆x = 3.86 × 10^-6 m