Answer to Question #149338 in General Chemistry for nsnndndjdjd
how many liters of chlorine will be needed to make 7.50 moles of C2H2Cl4 at STP
1
2020-12-08T05:32:30-0500
"C_2H_2 + 2Cl_2 = C_2H_2Cl_4"
"n(Cl_2) = 2n(C_2H_2Cl_4) = 2*7.50 = 15.00mol"
"V(Cl_2) = nV_m = 15.00*22.4 = 336L"
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