Answer to Question #149298 in General Chemistry for chris

Question

Compare the energetic favorability of MnO2 reduction by sulfide yielding S0 to the energetic favorability of MnO2 reduction by sulfide yielding SO42-...use numbers not words

Answer 1

K₂S + K₂MnO₄ + 2 H₂O → S + MnO₂ + 4 KOH

This is a redox reaction:

Mn^(vi) + 2 e - → Mn(^iv) (recovery)

S^-II-2 e - → S⁰ (oxidation)

 K₂MnO₄ is an oxidizer, K2S is a reducing agent.3 H₂S (g) + 8 KMnO₄ (aq) → 8 MnO₂ (s) + 3 K₂SO₄ (aq) + 2 KOH (aq) + 2 H₂O

This is a redox reaction:

8 Mn^vii + 24 e - → 8 Mn^iv (recovery)

3 S^-II-24 e - → 3 S^VI (oxidation)

KMnO₄ is an oxidizer, H₂S is a reducing agent.