Answer to Question #149267 in General Chemistry for sehba

Question #149267

What is the molarity of a solution containing 32g of K2SO4 IN 350 cm3 of solution?

Expert's answer

molarity: c=n/V

n(K₂SO₄)=m/M=32g / 174g/mol = 0.184mol

V=350cm³=0.35L

c(K₂SO₄)=0.184mol / 0.35L = 0.526 mol/L

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