Question #149172
A 25.0 L tank contains 2.0 kg of neon gas with a pressure of 98.0 atm at . How many kilograms of can fill the tank under the same pressure and temperature?
1
Expert's answer
2020-12-07T07:22:56-0500

Solution.

p×V=n×R×Tp \times V = n \times R \times T

n=mMn = \frac{m}{M}

n = 100 mol

T=p×Vn×RT = \frac{p \times V}{n \times R}

T = 298.73 K

n1=101325×0.0258.31×298.73n1 = \frac{101325 \times 0.025}{8.31 \times 298.73}

n1 = 1.02 mol

m(Ne)=n×M(Ne)m(Ne) = n \times M(Ne)

m(Ne) = 0.02 kg

Answer:

m(Ne) = 0.02 kg


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