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Answer to Question #148672 in General Chemistry for yaso
Question #148672
Calculate the mass of Cl2 that can be formed when 16.0 g of MnO2 reacted with 30.0 g of HCl according to the following chemical equation?
MnO2 + 4HCl MnCl2 + Cl2 + 2H2O
MnO2 + 4HCl MnCl2 + Cl2 + 2H2O
Expert's answer
In this reaction, MnO2 is the limiting reagent
87g MnO2 = 70g Cl2
1g MnO2 = 70/ 87 g Cl2
16 g MnO2 = 70× 16 / 87 g Cl2
= 12.87g Cl2
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