Question #148672
Calculate the mass of Cl2 that can be formed when 16.0 g of MnO2 reacted with 30.0 g of HCl according to the following chemical equation?
MnO2 + 4HCl  MnCl2 + Cl2 + 2H2O
1
Expert's answer
2020-12-06T13:29:14-0500

In this reaction, MnO2 is the limiting reagent

87g MnO2 = 70g Cl2

1g MnO2 = 70/ 87 g Cl2

16 g MnO2 = 70× 16 / 87 g Cl2

= 12.87g Cl2


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