Answer to Question #148510 in General Chemistry for DanYale WIlson

Question

Standardizing NaOH with KHP (molar mass 204.2 g/mole)

mass of flask + KHP 99.829 g final buret reading 25.35 mL

mass of flask 98.326 g initial buret reading 0.05 mL



Mass of KHP ___________ g Volume of NaOH, mL ____________



moles of KHP _____________ moles of NaOH needed neutralize KHP _______________



Molarity of NaOH? _______________

Answer 1

Standardizing NaOH with KHP (molar mass 204.2 g/mole)

mass of flask + KHP 99.829 g final buret reading 25.35 mL

mass of flask 98.326 g initial buret reading 0.05 mL

204.2g- 99.829g = 104.371g

98.326g- 0.05g = 98.276g of NaOH

1 mole of NaOH = 40g

Therefore :

1mole of NaOH = 40g

? = 98.276g

98.276g/40g = 2.4569moles

= 2.4569moles