Answer to Question #148281 in General Chemistry for Maria

Question

If a 2.50 l solution is made containing 1.98 miles of k3po4 what will the concentration of ions in the solution be

Answer 1

Assuming complete dissociation,

One mole of K₃PO₄ equals 4 moles of ions, i.e., 3 moles K⁺, 1 mole PO₄^3-.

1.98 moles equals 7.92 moles of ions.

Concentration = $No. of Moles / Volume of solvent (in L)$

Therefore, concentration of ions = 7.92/2.5 M

= 3.17 M (where M is no. of moles per Litre)