Volume of water = 60.0ml
Density of water at 25°C= 1.000g/ml
Mass of water = density x volume
Mass of water = 1.000 x 60 = 60g
Molar mass of water = 18g/mol
Number of moles of water = mass/molar mass = 60/18= 3.33mol
From the half equation
2H2O ------> O2 + 4H+ + 4e- (oxidation)
2 moles of water produces 1 mole of oxygen gas at STP
3.33 moles of water will therefore produce 1/2x 3.33 = 1.67 moles of O2 at STP
At STP, one mole of O2 occupies 22.4L
1.67mol will therefore occupy 1.67 x 22.4 = 37.41Litres
Therefore, the volume of oxygen gas obtained from the electrolysis is 37.41L.
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