2KHCO3 = K2CO3 + CO2 + H2O
0.69/138 = 0.005.
0.005 x 100 x 2 = 1.
1-0.69 = 0.31.
1-0.71 = 0.29.
0.29 x 138/62 = 0,64548387 g of K2CO3.
0,64548387 x 100%/0.69= 93,548387%.
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