Question #147253

Describe how the x- and y-coordinates of the given quadratic functions differ from the x- and y-coordinates of corresponding points of y=x^2

y=(x+7)^2

Expert's answer


y=(x+7)2y=(x+7)^2

=(x+7)(x+7)=(x+7)(x+7)

=x(x+7)+7(x+7)=x(x+7)+7(x+7)

=x2+7x+7x+49=x^2+7x+7x+49

=x2+14x+49=x^2+14x+49

a=1,b=14,andc=49a=1, b=14, and c=49

x=b/2ax=-b/2a

=14/2=-14/2

x=7x=-7

y=(x)2y=(x)^2

y=(7)2y=(-7)^2

=49=49

Coordinates(7,49)Coordinates (-7, 49)


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