We know that the equation is
ΔTf=Kf.Cm
Kf of benzene is =4.9k . molality-1
And Cm=1.77m
Hence ΔTf=4.9*1.77
=8.83k
And ΔTf=TF (pure solvent) − TF (solution)=8.83k
278.5k-TF(solution)=8.83k
TF(solution)=(278.5-8.83)k
=269.65k
Hence freezing point of solutions is 269.65k
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