Question

What is the freezing point of 1.77 m solution of CBr4 in C6H6?

Answer 1

We know that the equation is

ΔT_f=K_f.C_m

K_f of benzene is =4.9k . molality^-1

And C_m=1.77m

Hence ΔT_f=4.9*1.77

=8.83k

And ΔT_f=T_{F (pure solvent)} − T_{F (solution)}=8.83k

278.5k-T_F(solution)=8.83k

T_F(solution)=(278.5-8.83)k

=269.65k

Hence freezing point of solutions is 269.65k