first calculate the moles of calcium hydroxide(18.5/74.1)=0.2497moles
the equation of reaction gives a mole ratio between calcium hydroxide and hydrochloric acid as 1:2
therefor to find the moles used for HCl=(0.2497 × 2)=0.499moles
to find this vollume,(0.499 × 1000) ÷ 4.35=114.7ml
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