A) initial, pressure, P1 = 4.00 atm
= 4×760 torr
= 3040 torr
Temperature = 127 °C
So, T1 = 400 K
Final, pressure, P2 = 190 torr
Temperature,T2 = ?
As we know, P1/T1 = P2/T2
Or, T2 = (P2/P1)×T1
Or, T2 = (190/3040)× 400
= 25 K
So,
At 25 K temperaturethe pressure decrease to 190 torr
B) Molar mass of magnesium = 24.3 g/mol
So, 0.200 g magnesium = 8.23×10^-3 mole
Reaction of magnesium with Hydrochloric acid is,
Mg + 2HCl -------> MgCl2 + H2
1 mole of magnesium produces 1 mole H2
8.23×10^-3 mole magnesium produces
= 8.23×10^-3 mole of H2 gas
So,
number of moles of gas, n = 8.23×10^-3 mole
Temperature, = 25°C
T = 298 K
Pressure, P = 1 atm
We know, PV = nRT
Or, V = nRT/P
Or, V = 8.23×10^-3×0.082×298/1
= 0.2011 L
= 201.1 ml
So,
201.1 ml of hydrogen gas could be collected from the reaction at 1.0 atm and 25 °C
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