Mass of Li2CO3=x
Molar mass of Li2CO3=73.89g/mol
Volume of solution=0.1245L
Kw=1.0×10−4
pH of solution=1.96
pH=−log[H+][H+]=10−pH
10−4=1.0×10−4
Dissociation equation is;
Li2CO3⇋Li2++CO32−
1.0×10−4x= Ka Li2CO3=[Li2+][CO32−]
1.0×10−44.6×10−4(1.96) =9.016M
[CO32−]=9.016M
Mass of Li2CO3=?
Mass= LMol ]CO32−
= L9.016mol ×0.1245L
=1.1225CO32−
mLi2CO3=1.1225mol×73.89g/mol=82.94g
∴ Mass of Li2CO3=82.94g
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