Using the formula
PH=-log[H^+]
0.892=-log[H^x]
-0.892=log[H^x]
[H^x]= antilog(-0.892)
[H^x]=0.128
To find the conjugate concentration
We will divide the [H^+] conc by 4
Conc of (P2O7^-4)=0.128/4=0.032
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