Answer to Question #146965 in General Chemistry for liam donohue

Question

A 874.55ml solution consisting of 0.045 M Al(OH)3 was neutralised with 0.897L HBr.

What is the formula of the acid?

What moles of acid are present?

What is the concentration of the acid?

Answer 1

The equation for the reaction is

3HBr + Al(OH)3 -------- AlBr3 + 3H2O

A)The formula for the acid is HBr

B)We have 3 moles of the acid from the equation.

C)Tp find the conc of the acid we will use the formula;

CaVa = CbVb where

Ca= conc of acid Va=volume of acid

Cb= conc of base Vb=volume of base.

Converting the volume of the base to litre we have;874.5÷1000=0.875

So substituting our values we have;

Ca=Cb × Vb / Va

Ca=0.045×0.875/0.897

Ca = 0.044 M