Answer to Question #146790 in General Chemistry for qwerty

Question

1. Write the balanced nuclear equation describing alpha emission from Cm-242
2. Write the balanced nuclear equation describing beta emission that forms Al-28
3. What type of decay occurs with the transformation of Th-234 to Ra-210?
4. Write the balanced nuclear equations for the following
a) Formation of Mn-52 by positron emission
b) Formation of Ac-228 by beta emission
c) Formation of Np-232 by alpha decay
d) Mercury-201 undergoes electron capture
e) Thorium-231 decays to form protactinium

Answer 1

1. ²⁴²₉₆Cm -----> ²³⁸₉₄Pu + ⁴₂He

2. ²⁸₁₂Mg -------> ²⁸₁₃Al + ⁰_-1B (⁰_-1B is beta particle)

3.²³⁴₉₀Th ---------> ²¹⁰₇₈Ra + 6⁴₂He

Alpha decay involving emission of six molecules of Alpha particle per molecule of Thorium.

4a. ⁵²₂₆Fe -------> ⁵²₂₅Mn + ⁰₊₁B (⁰₊₁B is a positron particle)

b. ²²⁸₈₈Ra ---------> ²²⁸₈₉Ac + ⁰_-1B (⁰_-1B is beta particle)

c. ²³⁶₉₅Am --------> ²³²₉₃Np + ⁴₂He

d. ²⁰¹₈₀Hg + ⁰_-1e ---------> ²⁰¹₇₉Au

e. ²³¹₉₀Th ----------> ²³¹₉₁Pa + ⁰_-1B (⁰_-1B is beta particle)