Answer to Question #145833 in General Chemistry for gaile

Question

What volume of hydrogen will be produced at stp by the reaction 67.3 g of magnesium with excess water according to the following reaction?

Answer 1

Mg + 2H₂O $\rightarrow$ Mg(OH)₂ + H₂

moles of Mg taken = (67.3/24) = 2.80 moles

Moles of H₂ produce = 2.80moles

volume of H₂ at STP = 2.80× 22.4 L = 62.8 L