The equation of Ca(OH)2 reacting with HCl is
Ca(OH)2 + 2HCl = CaCl2 + 2H2O
Clearly,
1 mole of Ca(OH)2 reacting with HCl to produce 2 mole of H2O
2.70 moles of Ca(OH)2 reacting with HCl to produce (2×2.70) mole of H2O
= 5.4 moles of H2O
Molar mass of H2O = 18 g/mole
So,
mass of 5.4 moles of H2O = (18×5.4) g
= 97.2 g
Hence,
97.2 g of water will be produced from 2.70 moles of Ca(OH)2 reacting with HCl.
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