V1=0.1LT1=25°C=(273+25) 298KT2=98°C=(273+98) 371KV2= ?\begin{aligned} V_1 &= 0.1L\\ T_1 &= 25°C = (273 + 25)\ 298K\\ T_2 &= 98°C = (273 + 98)\ 371K\\ V_2 &=\ ? \end{aligned}V1T1T2V2=0.1L=25°C=(273+25) 298K=98°C=(273+98) 371K= ?
According to Charles's law,
V1T1=V2T2\dfrac{V_1}{T_1} = \dfrac{V_2}{T_2}T1V1=T2V2
0.1298=V2395\dfrac{0.1}{298} = \dfrac{V_2}{395}2980.1=395V2
V2=395×0.1298V_2 = \dfrac{395×0.1}{298}V2=298395×0.1
V2=0.133LV_2 = 0.133LV2=0.133L
∴\therefore∴ The final volume of the carbon dioxide gas is 0.133L.
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments