Question #145285
(C)=KH×P of H2
=0.00085mol/L.atm×0.97 atm
=8.2 mol/L.
1
Expert's answer
2020-11-20T09:59:13-0500

(C)

=KH×PofH2=0.00085mol/L.atm×0.97atm=8.2mol/L.=KH×P of H_2 =0.00085mol/L.atm×0.97 atm =8.2 mol/L.


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