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Answer to Question #145285 in General Chemistry for yonatan
Question #145285
(C)=KH×P of H2
=0.00085mol/L.atm×0.97 atm
=8.2 mol/L.
=0.00085mol/L.atm×0.97 atm
=8.2 mol/L.
Expert's answer
(C)
"=KH\u00d7P of H_2\n\n=0.00085mol\/L.atm\u00d70.97 atm\n\n=8.2 mol\/L."
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