Answer to Question #145285 in General Chemistry for yonatan

Question #145285
(C)=KH×P of H2
=0.00085mol/L.atm×0.97 atm
=8.2 mol/L.
1
Expert's answer
2020-11-20T09:59:13-0500

(C)

"=KH\u00d7P of H_2\n\n=0.00085mol\/L.atm\u00d70.97 atm\n\n=8.2 mol\/L."


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