Answer to Question #145115 in General Chemistry for liam donohue

Question

The temperature of the room the bottles were measured in was 21 degrees, the internal pressure of the bottle was 140.00 atm and the volume 30.0L. The mass of the gas in the bottle was found to be 7.65kg. Which gas is in the bottle? R=0.0821L

Answer 1

pV = nRT

140.00 atm x 30.0 L = n x 0.0821 L*atm/(mole*K) x (21+273.15) K

n = 174 moles

n = m/Mr

Mr = m/n = 7650 g / 174 moles = 43.9655 g/mol

Mr(CO₂) = 12 + 16x2 = 44 g/mol

CO₂