Question

There are two objects, m1 and m2 are connected by a rod of length 0.76 m. m1 and m2 are 165 grams and 210 grams respectively. Determine the moment of inertia of the masses about the axis of rotation AB at the center of the rod. Ignore the mass of the rod.

Answer 1

moment of inertia = m₁r₁² + m₂r₂²

I = 165 × (0.38)² + 210 × (0.38)²

I = 23.83 + 30.32

I = 62.15 gm²