Question

How many milliliters of oxygen gas at STP are released from heating 5.40 g of calcium chlorate?
Ca(ClO3)2(s)→CaCl2(s)+3O2(g)
Express your answer with the appropriate units.

Answer 1

Solution:

According to the reaction equation from 1 mol Ca(ClO₃)₂ of  are released 3 moles of O₂.

Molar mass of Ca(ClO₃)₂ = 206,98 g/mol

V of O2 = $(m Ca(ClO3_ )〗_2)/(M Ca(ClO_3)〖_2〗)× (3 mol O_2)/(1mol 〖Ca(ClO3)〗_2 )×22710ml/mol$  =  $5.40g/(206.98g/mol)×3mol/1mol×22710ml/mol$ = 1777,48 ml

Answer: V of O2 is 1777.48 ml