Question

Consider three photons of light A,B, and C. Show with calculations the relative order of the energies of the photon in J.
A is blue light of 450 Nm
B is light with frequency 6.46•10^-15 1/s
C is light with energy 3.46•10^-18 J

Answer 1

$E= hf$

h= 6.63×10^-34

A)E=( 6.63×10^-34)×(4.5×10^-7)

E= 2.98× 10^-40 J

B) E=( 6.63×10^-34)×(6.64×10^-15)

E= 4.4×10^-48J

C)3.46•10^-18 J

The relative order of energies is C, A, B