Answer to Question #144524 in General Chemistry for Lizzette

Question

How many grams of NH3 is produced if you react 42g N2?

Answer 1

Equation of reaction

3H_2(g)+N_2(g)=2NH_3(g)

Moles of N_2(g) that reacted

Moles=mass/RFM

=42g/28.02g/mole

=1.4958moles

Mole Ratio

N₂ : NH₃

1 : 2

Moles of NH₃= 2*1.4989= 2.9978moles

RMM of NH₃= 17.03g/mole

Mass of NH₃

Mass = moles*RMM

=17.03g/mole*2.9978moles

=51.05g of NH_3(g)