140 M = moles / .0143 L
.140 * .0143 L = 2.002 moles C12H22)11
2.002 moles C12H22)11 * 6.022 x 10^23 molecules / 1 mol C12H22 O 11 =
1.21 x10^24 molecules but the answer is
1.21 x 10 ^ 21
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