volume of the filled balloon = volume of 1.46 g of nitrogen gas (N2) at 0 °C and 1.0 atm (STP)
Temperature = 0°C
So, T = 273 K
Pressure, P = 1 atm
Mass of nitrogen gas, W = 2.46 g
Molar mass of nitrogen gas, M = 28 g/mol
So, number of moles of nitrogen gas,
n= (2.46/28) mol
From the ideal gas equation
PV = nRT
Or, V = nRT/P
Putting the values, and
R = 0.082 L.atm.mol-1.K-1 we get
So, V = (2.46/28)×0.082×273/1
=1.967 L
volume of 1.46 g of nitrogen gas (N2) at 0 °C and 1.0 atm (STP) = 1.967 L
Hence,
volume of the filled balloon = 1.967 L
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